Optimal. Leaf size=276 \[ -\frac {2 a (A b-a B) \sqrt {x}}{b^3}+\frac {2 (A b-a B) x^{5/2}}{5 b^2}+\frac {2 B x^{9/2}}{9 b}-\frac {a^{5/4} (A b-a B) \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}\right )}{\sqrt {2} b^{13/4}}+\frac {a^{5/4} (A b-a B) \tan ^{-1}\left (1+\frac {\sqrt {2} \sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}\right )}{\sqrt {2} b^{13/4}}-\frac {a^{5/4} (A b-a B) \log \left (\sqrt {a}-\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {x}+\sqrt {b} x\right )}{2 \sqrt {2} b^{13/4}}+\frac {a^{5/4} (A b-a B) \log \left (\sqrt {a}+\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {x}+\sqrt {b} x\right )}{2 \sqrt {2} b^{13/4}} \]
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Rubi [A]
time = 0.18, antiderivative size = 276, normalized size of antiderivative = 1.00, number of steps
used = 13, number of rules used = 9, integrand size = 22, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.409, Rules used = {470, 327, 335,
217, 1179, 642, 1176, 631, 210} \begin {gather*} -\frac {a^{5/4} (A b-a B) \text {ArcTan}\left (1-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}\right )}{\sqrt {2} b^{13/4}}+\frac {a^{5/4} (A b-a B) \text {ArcTan}\left (\frac {\sqrt {2} \sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}+1\right )}{\sqrt {2} b^{13/4}}-\frac {a^{5/4} (A b-a B) \log \left (-\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {x}+\sqrt {a}+\sqrt {b} x\right )}{2 \sqrt {2} b^{13/4}}+\frac {a^{5/4} (A b-a B) \log \left (\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {x}+\sqrt {a}+\sqrt {b} x\right )}{2 \sqrt {2} b^{13/4}}-\frac {2 a \sqrt {x} (A b-a B)}{b^3}+\frac {2 x^{5/2} (A b-a B)}{5 b^2}+\frac {2 B x^{9/2}}{9 b} \end {gather*}
Antiderivative was successfully verified.
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Rule 210
Rule 217
Rule 327
Rule 335
Rule 470
Rule 631
Rule 642
Rule 1176
Rule 1179
Rubi steps
\begin {align*} \int \frac {x^{7/2} \left (A+B x^2\right )}{a+b x^2} \, dx &=\frac {2 B x^{9/2}}{9 b}-\frac {\left (2 \left (-\frac {9 A b}{2}+\frac {9 a B}{2}\right )\right ) \int \frac {x^{7/2}}{a+b x^2} \, dx}{9 b}\\ &=\frac {2 (A b-a B) x^{5/2}}{5 b^2}+\frac {2 B x^{9/2}}{9 b}-\frac {(a (A b-a B)) \int \frac {x^{3/2}}{a+b x^2} \, dx}{b^2}\\ &=-\frac {2 a (A b-a B) \sqrt {x}}{b^3}+\frac {2 (A b-a B) x^{5/2}}{5 b^2}+\frac {2 B x^{9/2}}{9 b}+\frac {\left (a^2 (A b-a B)\right ) \int \frac {1}{\sqrt {x} \left (a+b x^2\right )} \, dx}{b^3}\\ &=-\frac {2 a (A b-a B) \sqrt {x}}{b^3}+\frac {2 (A b-a B) x^{5/2}}{5 b^2}+\frac {2 B x^{9/2}}{9 b}+\frac {\left (2 a^2 (A b-a B)\right ) \text {Subst}\left (\int \frac {1}{a+b x^4} \, dx,x,\sqrt {x}\right )}{b^3}\\ &=-\frac {2 a (A b-a B) \sqrt {x}}{b^3}+\frac {2 (A b-a B) x^{5/2}}{5 b^2}+\frac {2 B x^{9/2}}{9 b}+\frac {\left (a^{3/2} (A b-a B)\right ) \text {Subst}\left (\int \frac {\sqrt {a}-\sqrt {b} x^2}{a+b x^4} \, dx,x,\sqrt {x}\right )}{b^3}+\frac {\left (a^{3/2} (A b-a B)\right ) \text {Subst}\left (\int \frac {\sqrt {a}+\sqrt {b} x^2}{a+b x^4} \, dx,x,\sqrt {x}\right )}{b^3}\\ &=-\frac {2 a (A b-a B) \sqrt {x}}{b^3}+\frac {2 (A b-a B) x^{5/2}}{5 b^2}+\frac {2 B x^{9/2}}{9 b}+\frac {\left (a^{3/2} (A b-a B)\right ) \text {Subst}\left (\int \frac {1}{\frac {\sqrt {a}}{\sqrt {b}}-\frac {\sqrt {2} \sqrt [4]{a} x}{\sqrt [4]{b}}+x^2} \, dx,x,\sqrt {x}\right )}{2 b^{7/2}}+\frac {\left (a^{3/2} (A b-a B)\right ) \text {Subst}\left (\int \frac {1}{\frac {\sqrt {a}}{\sqrt {b}}+\frac {\sqrt {2} \sqrt [4]{a} x}{\sqrt [4]{b}}+x^2} \, dx,x,\sqrt {x}\right )}{2 b^{7/2}}-\frac {\left (a^{5/4} (A b-a B)\right ) \text {Subst}\left (\int \frac {\frac {\sqrt {2} \sqrt [4]{a}}{\sqrt [4]{b}}+2 x}{-\frac {\sqrt {a}}{\sqrt {b}}-\frac {\sqrt {2} \sqrt [4]{a} x}{\sqrt [4]{b}}-x^2} \, dx,x,\sqrt {x}\right )}{2 \sqrt {2} b^{13/4}}-\frac {\left (a^{5/4} (A b-a B)\right ) \text {Subst}\left (\int \frac {\frac {\sqrt {2} \sqrt [4]{a}}{\sqrt [4]{b}}-2 x}{-\frac {\sqrt {a}}{\sqrt {b}}+\frac {\sqrt {2} \sqrt [4]{a} x}{\sqrt [4]{b}}-x^2} \, dx,x,\sqrt {x}\right )}{2 \sqrt {2} b^{13/4}}\\ &=-\frac {2 a (A b-a B) \sqrt {x}}{b^3}+\frac {2 (A b-a B) x^{5/2}}{5 b^2}+\frac {2 B x^{9/2}}{9 b}-\frac {a^{5/4} (A b-a B) \log \left (\sqrt {a}-\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {x}+\sqrt {b} x\right )}{2 \sqrt {2} b^{13/4}}+\frac {a^{5/4} (A b-a B) \log \left (\sqrt {a}+\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {x}+\sqrt {b} x\right )}{2 \sqrt {2} b^{13/4}}+\frac {\left (a^{5/4} (A b-a B)\right ) \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}\right )}{\sqrt {2} b^{13/4}}-\frac {\left (a^{5/4} (A b-a B)\right ) \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1+\frac {\sqrt {2} \sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}\right )}{\sqrt {2} b^{13/4}}\\ &=-\frac {2 a (A b-a B) \sqrt {x}}{b^3}+\frac {2 (A b-a B) x^{5/2}}{5 b^2}+\frac {2 B x^{9/2}}{9 b}-\frac {a^{5/4} (A b-a B) \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}\right )}{\sqrt {2} b^{13/4}}+\frac {a^{5/4} (A b-a B) \tan ^{-1}\left (1+\frac {\sqrt {2} \sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}\right )}{\sqrt {2} b^{13/4}}-\frac {a^{5/4} (A b-a B) \log \left (\sqrt {a}-\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {x}+\sqrt {b} x\right )}{2 \sqrt {2} b^{13/4}}+\frac {a^{5/4} (A b-a B) \log \left (\sqrt {a}+\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {x}+\sqrt {b} x\right )}{2 \sqrt {2} b^{13/4}}\\ \end {align*}
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Mathematica [A]
time = 0.28, size = 173, normalized size = 0.63 \begin {gather*} \frac {2 \sqrt {x} \left (-45 a A b+45 a^2 B+9 A b^2 x^2-9 a b B x^2+5 b^2 B x^4\right )}{45 b^3}+\frac {a^{5/4} (-A b+a B) \tan ^{-1}\left (\frac {\sqrt {a}-\sqrt {b} x}{\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {x}}\right )}{\sqrt {2} b^{13/4}}-\frac {a^{5/4} (-A b+a B) \tanh ^{-1}\left (\frac {\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {x}}{\sqrt {a}+\sqrt {b} x}\right )}{\sqrt {2} b^{13/4}} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.09, size = 164, normalized size = 0.59
method | result | size |
derivativedivides | \(-\frac {2 \left (-\frac {b^{2} B \,x^{\frac {9}{2}}}{9}-\frac {A \,b^{2} x^{\frac {5}{2}}}{5}+\frac {B a b \,x^{\frac {5}{2}}}{5}+a b A \sqrt {x}-a^{2} B \sqrt {x}\right )}{b^{3}}+\frac {a \left (A b -B a \right ) \left (\frac {a}{b}\right )^{\frac {1}{4}} \sqrt {2}\, \left (\ln \left (\frac {x +\left (\frac {a}{b}\right )^{\frac {1}{4}} \sqrt {x}\, \sqrt {2}+\sqrt {\frac {a}{b}}}{x -\left (\frac {a}{b}\right )^{\frac {1}{4}} \sqrt {x}\, \sqrt {2}+\sqrt {\frac {a}{b}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {x}}{\left (\frac {a}{b}\right )^{\frac {1}{4}}}+1\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {x}}{\left (\frac {a}{b}\right )^{\frac {1}{4}}}-1\right )\right )}{4 b^{3}}\) | \(164\) |
default | \(-\frac {2 \left (-\frac {b^{2} B \,x^{\frac {9}{2}}}{9}-\frac {A \,b^{2} x^{\frac {5}{2}}}{5}+\frac {B a b \,x^{\frac {5}{2}}}{5}+a b A \sqrt {x}-a^{2} B \sqrt {x}\right )}{b^{3}}+\frac {a \left (A b -B a \right ) \left (\frac {a}{b}\right )^{\frac {1}{4}} \sqrt {2}\, \left (\ln \left (\frac {x +\left (\frac {a}{b}\right )^{\frac {1}{4}} \sqrt {x}\, \sqrt {2}+\sqrt {\frac {a}{b}}}{x -\left (\frac {a}{b}\right )^{\frac {1}{4}} \sqrt {x}\, \sqrt {2}+\sqrt {\frac {a}{b}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {x}}{\left (\frac {a}{b}\right )^{\frac {1}{4}}}+1\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {x}}{\left (\frac {a}{b}\right )^{\frac {1}{4}}}-1\right )\right )}{4 b^{3}}\) | \(164\) |
risch | \(-\frac {2 \left (-5 b^{2} B \,x^{4}-9 A \,b^{2} x^{2}+9 B a b \,x^{2}+45 a b A -45 a^{2} B \right ) \sqrt {x}}{45 b^{3}}+\frac {a \left (\frac {a}{b}\right )^{\frac {1}{4}} \sqrt {2}\, A \arctan \left (\frac {\sqrt {2}\, \sqrt {x}}{\left (\frac {a}{b}\right )^{\frac {1}{4}}}+1\right )}{2 b^{2}}+\frac {a \left (\frac {a}{b}\right )^{\frac {1}{4}} \sqrt {2}\, A \arctan \left (\frac {\sqrt {2}\, \sqrt {x}}{\left (\frac {a}{b}\right )^{\frac {1}{4}}}-1\right )}{2 b^{2}}+\frac {a \left (\frac {a}{b}\right )^{\frac {1}{4}} \sqrt {2}\, A \ln \left (\frac {x +\left (\frac {a}{b}\right )^{\frac {1}{4}} \sqrt {x}\, \sqrt {2}+\sqrt {\frac {a}{b}}}{x -\left (\frac {a}{b}\right )^{\frac {1}{4}} \sqrt {x}\, \sqrt {2}+\sqrt {\frac {a}{b}}}\right )}{4 b^{2}}-\frac {a^{2} \left (\frac {a}{b}\right )^{\frac {1}{4}} \sqrt {2}\, B \arctan \left (\frac {\sqrt {2}\, \sqrt {x}}{\left (\frac {a}{b}\right )^{\frac {1}{4}}}+1\right )}{2 b^{3}}-\frac {a^{2} \left (\frac {a}{b}\right )^{\frac {1}{4}} \sqrt {2}\, B \arctan \left (\frac {\sqrt {2}\, \sqrt {x}}{\left (\frac {a}{b}\right )^{\frac {1}{4}}}-1\right )}{2 b^{3}}-\frac {a^{2} \left (\frac {a}{b}\right )^{\frac {1}{4}} \sqrt {2}\, B \ln \left (\frac {x +\left (\frac {a}{b}\right )^{\frac {1}{4}} \sqrt {x}\, \sqrt {2}+\sqrt {\frac {a}{b}}}{x -\left (\frac {a}{b}\right )^{\frac {1}{4}} \sqrt {x}\, \sqrt {2}+\sqrt {\frac {a}{b}}}\right )}{4 b^{3}}\) | \(326\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.50, size = 259, normalized size = 0.94 \begin {gather*} -\frac {{\left (\frac {2 \, \sqrt {2} {\left (B a - A b\right )} \arctan \left (\frac {\sqrt {2} {\left (\sqrt {2} a^{\frac {1}{4}} b^{\frac {1}{4}} + 2 \, \sqrt {b} \sqrt {x}\right )}}{2 \, \sqrt {\sqrt {a} \sqrt {b}}}\right )}{\sqrt {a} \sqrt {\sqrt {a} \sqrt {b}}} + \frac {2 \, \sqrt {2} {\left (B a - A b\right )} \arctan \left (-\frac {\sqrt {2} {\left (\sqrt {2} a^{\frac {1}{4}} b^{\frac {1}{4}} - 2 \, \sqrt {b} \sqrt {x}\right )}}{2 \, \sqrt {\sqrt {a} \sqrt {b}}}\right )}{\sqrt {a} \sqrt {\sqrt {a} \sqrt {b}}} + \frac {\sqrt {2} {\left (B a - A b\right )} \log \left (\sqrt {2} a^{\frac {1}{4}} b^{\frac {1}{4}} \sqrt {x} + \sqrt {b} x + \sqrt {a}\right )}{a^{\frac {3}{4}} b^{\frac {1}{4}}} - \frac {\sqrt {2} {\left (B a - A b\right )} \log \left (-\sqrt {2} a^{\frac {1}{4}} b^{\frac {1}{4}} \sqrt {x} + \sqrt {b} x + \sqrt {a}\right )}{a^{\frac {3}{4}} b^{\frac {1}{4}}}\right )} a^{2}}{4 \, b^{3}} + \frac {2 \, {\left (5 \, B b^{2} x^{\frac {9}{2}} - 9 \, {\left (B a b - A b^{2}\right )} x^{\frac {5}{2}} + 45 \, {\left (B a^{2} - A a b\right )} \sqrt {x}\right )}}{45 \, b^{3}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] Leaf count of result is larger than twice the leaf count of optimal. 714 vs.
\(2 (199) = 398\).
time = 1.42, size = 714, normalized size = 2.59 \begin {gather*} \frac {180 \, b^{3} \left (-\frac {B^{4} a^{9} - 4 \, A B^{3} a^{8} b + 6 \, A^{2} B^{2} a^{7} b^{2} - 4 \, A^{3} B a^{6} b^{3} + A^{4} a^{5} b^{4}}{b^{13}}\right )^{\frac {1}{4}} \arctan \left (\frac {\sqrt {b^{6} \sqrt {-\frac {B^{4} a^{9} - 4 \, A B^{3} a^{8} b + 6 \, A^{2} B^{2} a^{7} b^{2} - 4 \, A^{3} B a^{6} b^{3} + A^{4} a^{5} b^{4}}{b^{13}}} + {\left (B^{2} a^{4} - 2 \, A B a^{3} b + A^{2} a^{2} b^{2}\right )} x} b^{10} \left (-\frac {B^{4} a^{9} - 4 \, A B^{3} a^{8} b + 6 \, A^{2} B^{2} a^{7} b^{2} - 4 \, A^{3} B a^{6} b^{3} + A^{4} a^{5} b^{4}}{b^{13}}\right )^{\frac {3}{4}} + {\left (B a^{2} b^{10} - A a b^{11}\right )} \sqrt {x} \left (-\frac {B^{4} a^{9} - 4 \, A B^{3} a^{8} b + 6 \, A^{2} B^{2} a^{7} b^{2} - 4 \, A^{3} B a^{6} b^{3} + A^{4} a^{5} b^{4}}{b^{13}}\right )^{\frac {3}{4}}}{B^{4} a^{9} - 4 \, A B^{3} a^{8} b + 6 \, A^{2} B^{2} a^{7} b^{2} - 4 \, A^{3} B a^{6} b^{3} + A^{4} a^{5} b^{4}}\right ) + 45 \, b^{3} \left (-\frac {B^{4} a^{9} - 4 \, A B^{3} a^{8} b + 6 \, A^{2} B^{2} a^{7} b^{2} - 4 \, A^{3} B a^{6} b^{3} + A^{4} a^{5} b^{4}}{b^{13}}\right )^{\frac {1}{4}} \log \left (b^{3} \left (-\frac {B^{4} a^{9} - 4 \, A B^{3} a^{8} b + 6 \, A^{2} B^{2} a^{7} b^{2} - 4 \, A^{3} B a^{6} b^{3} + A^{4} a^{5} b^{4}}{b^{13}}\right )^{\frac {1}{4}} - {\left (B a^{2} - A a b\right )} \sqrt {x}\right ) - 45 \, b^{3} \left (-\frac {B^{4} a^{9} - 4 \, A B^{3} a^{8} b + 6 \, A^{2} B^{2} a^{7} b^{2} - 4 \, A^{3} B a^{6} b^{3} + A^{4} a^{5} b^{4}}{b^{13}}\right )^{\frac {1}{4}} \log \left (-b^{3} \left (-\frac {B^{4} a^{9} - 4 \, A B^{3} a^{8} b + 6 \, A^{2} B^{2} a^{7} b^{2} - 4 \, A^{3} B a^{6} b^{3} + A^{4} a^{5} b^{4}}{b^{13}}\right )^{\frac {1}{4}} - {\left (B a^{2} - A a b\right )} \sqrt {x}\right ) + 4 \, {\left (5 \, B b^{2} x^{4} + 45 \, B a^{2} - 45 \, A a b - 9 \, {\left (B a b - A b^{2}\right )} x^{2}\right )} \sqrt {x}}{90 \, b^{3}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A]
time = 38.64, size = 326, normalized size = 1.18 \begin {gather*} \begin {cases} \tilde {\infty } \left (\frac {2 A x^{\frac {5}{2}}}{5} + \frac {2 B x^{\frac {9}{2}}}{9}\right ) & \text {for}\: a = 0 \wedge b = 0 \\\frac {\frac {2 A x^{\frac {9}{2}}}{9} + \frac {2 B x^{\frac {13}{2}}}{13}}{a} & \text {for}\: b = 0 \\\frac {\frac {2 A x^{\frac {5}{2}}}{5} + \frac {2 B x^{\frac {9}{2}}}{9}}{b} & \text {for}\: a = 0 \\- \frac {2 A a \sqrt {x}}{b^{2}} - \frac {A a \sqrt [4]{- \frac {a}{b}} \log {\left (\sqrt {x} - \sqrt [4]{- \frac {a}{b}} \right )}}{2 b^{2}} + \frac {A a \sqrt [4]{- \frac {a}{b}} \log {\left (\sqrt {x} + \sqrt [4]{- \frac {a}{b}} \right )}}{2 b^{2}} + \frac {A a \sqrt [4]{- \frac {a}{b}} \operatorname {atan}{\left (\frac {\sqrt {x}}{\sqrt [4]{- \frac {a}{b}}} \right )}}{b^{2}} + \frac {2 A x^{\frac {5}{2}}}{5 b} + \frac {2 B a^{2} \sqrt {x}}{b^{3}} + \frac {B a^{2} \sqrt [4]{- \frac {a}{b}} \log {\left (\sqrt {x} - \sqrt [4]{- \frac {a}{b}} \right )}}{2 b^{3}} - \frac {B a^{2} \sqrt [4]{- \frac {a}{b}} \log {\left (\sqrt {x} + \sqrt [4]{- \frac {a}{b}} \right )}}{2 b^{3}} - \frac {B a^{2} \sqrt [4]{- \frac {a}{b}} \operatorname {atan}{\left (\frac {\sqrt {x}}{\sqrt [4]{- \frac {a}{b}}} \right )}}{b^{3}} - \frac {2 B a x^{\frac {5}{2}}}{5 b^{2}} + \frac {2 B x^{\frac {9}{2}}}{9 b} & \text {otherwise} \end {cases} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 1.00, size = 298, normalized size = 1.08 \begin {gather*} -\frac {\sqrt {2} {\left (\left (a b^{3}\right )^{\frac {1}{4}} B a^{2} - \left (a b^{3}\right )^{\frac {1}{4}} A a b\right )} \arctan \left (\frac {\sqrt {2} {\left (\sqrt {2} \left (\frac {a}{b}\right )^{\frac {1}{4}} + 2 \, \sqrt {x}\right )}}{2 \, \left (\frac {a}{b}\right )^{\frac {1}{4}}}\right )}{2 \, b^{4}} - \frac {\sqrt {2} {\left (\left (a b^{3}\right )^{\frac {1}{4}} B a^{2} - \left (a b^{3}\right )^{\frac {1}{4}} A a b\right )} \arctan \left (-\frac {\sqrt {2} {\left (\sqrt {2} \left (\frac {a}{b}\right )^{\frac {1}{4}} - 2 \, \sqrt {x}\right )}}{2 \, \left (\frac {a}{b}\right )^{\frac {1}{4}}}\right )}{2 \, b^{4}} - \frac {\sqrt {2} {\left (\left (a b^{3}\right )^{\frac {1}{4}} B a^{2} - \left (a b^{3}\right )^{\frac {1}{4}} A a b\right )} \log \left (\sqrt {2} \sqrt {x} \left (\frac {a}{b}\right )^{\frac {1}{4}} + x + \sqrt {\frac {a}{b}}\right )}{4 \, b^{4}} + \frac {\sqrt {2} {\left (\left (a b^{3}\right )^{\frac {1}{4}} B a^{2} - \left (a b^{3}\right )^{\frac {1}{4}} A a b\right )} \log \left (-\sqrt {2} \sqrt {x} \left (\frac {a}{b}\right )^{\frac {1}{4}} + x + \sqrt {\frac {a}{b}}\right )}{4 \, b^{4}} + \frac {2 \, {\left (5 \, B b^{8} x^{\frac {9}{2}} - 9 \, B a b^{7} x^{\frac {5}{2}} + 9 \, A b^{8} x^{\frac {5}{2}} + 45 \, B a^{2} b^{6} \sqrt {x} - 45 \, A a b^{7} \sqrt {x}\right )}}{45 \, b^{9}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 0.20, size = 788, normalized size = 2.86 \begin {gather*} x^{5/2}\,\left (\frac {2\,A}{5\,b}-\frac {2\,B\,a}{5\,b^2}\right )+\frac {2\,B\,x^{9/2}}{9\,b}-\frac {{\left (-a\right )}^{5/4}\,\mathrm {atan}\left (\frac {\frac {{\left (-a\right )}^{5/4}\,\left (\frac {16\,\sqrt {x}\,\left (A^2\,a^4\,b^2-2\,A\,B\,a^5\,b+B^2\,a^6\right )}{b^3}-\frac {{\left (-a\right )}^{5/4}\,\left (A\,b-B\,a\right )\,\left (32\,B\,a^4-32\,A\,a^3\,b\right )\,1{}\mathrm {i}}{2\,b^{13/4}}\right )\,\left (A\,b-B\,a\right )}{2\,b^{13/4}}+\frac {{\left (-a\right )}^{5/4}\,\left (\frac {16\,\sqrt {x}\,\left (A^2\,a^4\,b^2-2\,A\,B\,a^5\,b+B^2\,a^6\right )}{b^3}+\frac {{\left (-a\right )}^{5/4}\,\left (A\,b-B\,a\right )\,\left (32\,B\,a^4-32\,A\,a^3\,b\right )\,1{}\mathrm {i}}{2\,b^{13/4}}\right )\,\left (A\,b-B\,a\right )}{2\,b^{13/4}}}{\frac {{\left (-a\right )}^{5/4}\,\left (\frac {16\,\sqrt {x}\,\left (A^2\,a^4\,b^2-2\,A\,B\,a^5\,b+B^2\,a^6\right )}{b^3}-\frac {{\left (-a\right )}^{5/4}\,\left (A\,b-B\,a\right )\,\left (32\,B\,a^4-32\,A\,a^3\,b\right )\,1{}\mathrm {i}}{2\,b^{13/4}}\right )\,\left (A\,b-B\,a\right )\,1{}\mathrm {i}}{2\,b^{13/4}}-\frac {{\left (-a\right )}^{5/4}\,\left (\frac {16\,\sqrt {x}\,\left (A^2\,a^4\,b^2-2\,A\,B\,a^5\,b+B^2\,a^6\right )}{b^3}+\frac {{\left (-a\right )}^{5/4}\,\left (A\,b-B\,a\right )\,\left (32\,B\,a^4-32\,A\,a^3\,b\right )\,1{}\mathrm {i}}{2\,b^{13/4}}\right )\,\left (A\,b-B\,a\right )\,1{}\mathrm {i}}{2\,b^{13/4}}}\right )\,\left (A\,b-B\,a\right )}{b^{13/4}}-\frac {a\,\sqrt {x}\,\left (\frac {2\,A}{b}-\frac {2\,B\,a}{b^2}\right )}{b}-\frac {{\left (-a\right )}^{5/4}\,\mathrm {atan}\left (\frac {\frac {{\left (-a\right )}^{5/4}\,\left (\frac {16\,\sqrt {x}\,\left (A^2\,a^4\,b^2-2\,A\,B\,a^5\,b+B^2\,a^6\right )}{b^3}-\frac {{\left (-a\right )}^{5/4}\,\left (A\,b-B\,a\right )\,\left (32\,B\,a^4-32\,A\,a^3\,b\right )}{2\,b^{13/4}}\right )\,\left (A\,b-B\,a\right )\,1{}\mathrm {i}}{2\,b^{13/4}}+\frac {{\left (-a\right )}^{5/4}\,\left (\frac {16\,\sqrt {x}\,\left (A^2\,a^4\,b^2-2\,A\,B\,a^5\,b+B^2\,a^6\right )}{b^3}+\frac {{\left (-a\right )}^{5/4}\,\left (A\,b-B\,a\right )\,\left (32\,B\,a^4-32\,A\,a^3\,b\right )}{2\,b^{13/4}}\right )\,\left (A\,b-B\,a\right )\,1{}\mathrm {i}}{2\,b^{13/4}}}{\frac {{\left (-a\right )}^{5/4}\,\left (\frac {16\,\sqrt {x}\,\left (A^2\,a^4\,b^2-2\,A\,B\,a^5\,b+B^2\,a^6\right )}{b^3}-\frac {{\left (-a\right )}^{5/4}\,\left (A\,b-B\,a\right )\,\left (32\,B\,a^4-32\,A\,a^3\,b\right )}{2\,b^{13/4}}\right )\,\left (A\,b-B\,a\right )}{2\,b^{13/4}}-\frac {{\left (-a\right )}^{5/4}\,\left (\frac {16\,\sqrt {x}\,\left (A^2\,a^4\,b^2-2\,A\,B\,a^5\,b+B^2\,a^6\right )}{b^3}+\frac {{\left (-a\right )}^{5/4}\,\left (A\,b-B\,a\right )\,\left (32\,B\,a^4-32\,A\,a^3\,b\right )}{2\,b^{13/4}}\right )\,\left (A\,b-B\,a\right )}{2\,b^{13/4}}}\right )\,\left (A\,b-B\,a\right )\,1{}\mathrm {i}}{b^{13/4}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
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